NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Exercise 14.2

Ex 14.2 Class 6 Maths Question 1.
Draw a line segment of length 7.3 cm using ruler.
Solution:
Step I: Mark at point P.
Step II : Place the O mark of the ruler against the point P.
Step III : Mark a point Q at a distance of 7.3 cm from P.
Step IV : Join P and Q.

Thus PQ¯¯¯¯¯¯¯¯ is the line segment of length 7.3 cm.

Ex 14.2 Class 6 Maths Question 2.
Construct a line segment of length 5.6 cm using ruler and compass.
Solution:
Step I: Draw any line L of suitable lengths.
Step II : Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.
Step III : Place the needle at any point A at the line and draw an arc to cut l at B.

Thus, AB¯¯¯¯¯¯¯¯ is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3.
Construct AB¯¯¯¯¯¯¯¯ of length 7.8 cm. From this, cut off AC¯¯¯¯¯¯¯¯ of length 4.7 cm. Measure BC¯¯¯¯¯¯¯¯ .
Solution:
Given that AB¯¯¯¯¯¯¯¯ = 7.8 cm and AC¯¯¯¯¯¯¯¯ = 4.7 cm.
Step I : Place zero mark of the ruler at A.
Step II : Mark a point B at a distance of 7.8 cm from A.
Step III : Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.
Step IV : On measuring the length of BC, we find that BC¯¯¯¯¯¯¯¯ = 3.1 cm.

Ex 14.2 Class 6 Maths Question 4.
Given AB¯¯¯¯¯¯¯¯ of length 3.9 cm. Construct PQ¯¯¯¯¯¯¯¯ such that the length of PQ¯¯¯¯¯¯¯¯ is twice that of AB¯¯¯¯¯¯¯¯. Verify by measurement.

(Hint : Construct PX¯¯¯¯¯¯¯¯ such that the length of PX¯¯¯¯¯¯¯¯ = length of AB¯¯¯¯¯¯¯¯ then cut off XQ¯¯¯¯¯¯¯¯ such that XQ¯¯¯¯¯¯¯¯ also has the length of AB¯¯¯¯¯¯¯¯.
Solution:
Step I: Draw a line l of suitable length.
Step II: Draw AB¯¯¯¯¯¯¯¯ = 3.9 cm
Step III: From the line, construct PX¯¯¯¯¯¯¯¯ = AB¯¯¯¯¯¯¯¯ = 3.9 cm.
Step IV: Again construct XQ¯¯¯¯¯¯¯¯= AB¯¯¯¯¯¯¯¯ =3.9 cm
Verification: PX¯¯¯¯¯¯¯¯ + XQ¯¯¯¯¯¯¯¯ = AB¯¯¯¯¯¯¯¯ + AB¯¯¯¯¯¯¯¯

Thus twice of AB¯¯¯¯¯¯¯¯ is equal to PQ¯¯¯¯¯¯¯¯

Ex 14.2 Class 6 Maths Question 5.
Given AB¯¯¯¯¯¯¯¯ of length 7.3 cm and CD¯¯¯¯¯¯¯¯ of length 3.4 cm, construct a line segment XY¯¯¯¯¯¯¯¯ such that the length of XY is equal to the difference between the length of AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ . Verify the measurement.
Solution:
Step I : Construct AB¯¯¯¯¯¯¯¯ = 7.3 cm and CD¯¯¯¯¯¯¯¯ = 3.4 cm.

Step II: Take a point P on the given line l.
Step III: Construct PR¯¯¯¯¯¯¯¯ such that PR¯¯¯¯¯¯¯¯ = AB¯¯¯¯¯¯¯¯ = AB¯¯¯¯¯¯¯¯ = 7.3 cm.
Step IV:Construct RQ¯¯¯¯¯¯¯¯ = CD¯¯¯¯¯¯¯¯ = 3.4 cm such that PQ = AB¯¯¯¯¯¯¯¯ – CD¯¯¯¯¯¯¯¯ .
Verification : On measuring, we observe that PQ¯¯¯¯¯¯¯¯ = 3.9 cm = 7.3 cm 3.4 cm.
= AB¯¯¯¯¯¯¯¯ – CD¯¯¯¯¯¯¯¯
Thus, PQ¯¯¯¯¯¯¯¯ = AB¯¯¯¯¯¯¯¯ – CD¯¯¯¯¯¯¯¯.

NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

Amresh Academy

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